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Question

Find the magnitude of component of electric field due to a dipole at a point P along perpendicular to the line joining point P and centre of dipole O as shown in figure.


A
4.41×103 N/C
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B
3.41×103 N/C
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C
2.41×103 N/C
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D
1.41×103 N/C
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Solution

The correct option is D 1.41×103 N/C
Given:
Distance of charges from centre of dipole, l=1 mm

Distance of point P from centre of dipole, x=4 m

Magnitude of charge, q=10 nC

Angle made of line joining point P and centre of dipole with axis of dipole, θ=30

We know that magnitude of component of electric field at a point P far away (4 m>>1 mm) along perpendicular to the line joining of point P and centre of dipole due to a dipole is given by

E=kpsinθx3=2kqlsinθx3

E=2×9×109×10×109×1×103×sin3043

E=1.41×103 N/C

Hence, option (a) is correct.

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