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Question

Find the magnitude of the standard electrode potential of MnO4/MnO2. The standard electrode potentials of MnO4/Mn2+=1.51 V and MnO2/Mn2+=1.23 V.

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Solution

Given:
(i) MnO4 + 8H+ + 5eMn2+ + 4H2O ....Go1

(ii) MnO2 + 4H+ + 2eMn2+ + 2H2O ....Go2

substracting equation (ii) from (i) give the required equation, i.e.,
MnO4 + 4H+ + 3eMnO2 + 2H2O ....Go3

Go3=Go1Go2
3FEo=5FEo1(2FEo2)
Eo3=(5×1.51)V(2×1.23)V3
Eo3=1.7 V


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