Find the mass of 1-2044 - 1023 molecules of limewater-

The correct option is D 14.8 g Moles of 1.2044×10^23 moles of limewater is : =1.2044×10^23/6.022×10^23=0.2 moles Molecular mass of limewater or Ca(OH)_2 = 74 ...

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Byju's Answer

Standard VIII

Chemistry

Molecular Mass

Find the mass...

Question

Find the mass of $1.2044 \times 10^{23}$ molecules of limewater.

148 g

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14.8 g

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57 g

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5.7 g

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Solution

The correct option is B
14.8 g

Moles of $1.2044 \times 10^{23}$ moles of limewater is :
$= \frac{1.2044 \times 10^{23}}{6.022 \times 10^{23}} = 0.2$ moles

Molecular mass of limewater or $C a (O H)_{2}$ = 74
$∴$ Molecular mass $0.2$ moles of $C a (O H)_{2} = 0.2 \times 74 = 14.8 g$

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Which of the following correctly represents 360 g of water?

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(ii) 20 moles of water

(iii) $6.022 \times 10^{23}$ molecules of water

(iv)

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Question 1
Which of the following correctly represents 360 g of water?

(i) 2 moles of $H_{2} O$

(ii) 20 moles of water

(iii) $6.022 \times 10^{23}$ molecules of water

(iv)

1.2044 \times 10^{25}

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(a) (i)
(b) (i) and (iv)
(c) (ii) and (iii)
(d) (ii) and (iv)

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Find the mass of 1.2044×1023 molecules of limewater.

The correct option is B 14.8 g Moles of 1.2044×1023 moles of limewater is : =1.2044×10236.022×1023=0.2 moles Molecular mass of limewater or Ca(OH)2 = 74 ∴ Molecular mass 0.2 moles of Ca(OH)2=0.2×74=14.8 g

Find the mass of $1.2044 \times 10^{23}$ molecules of limewater.

The correct option is B
14.8 g

Moles of $1.2044 \times 10^{23}$ moles of limewater is :
$= \frac{1.2044 \times 10^{23}}{6.022 \times 10^{23}} = 0.2$ moles

Molecular mass of limewater or $C a (O H)_{2}$ = 74
$∴$ Molecular mass $0.2$ moles of $C a (O H)_{2} = 0.2 \times 74 = 14.8 g$