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Standard VIII

Physics

Loudness

Find the maxi...

Question

Find the maximum displacement in the fluid of inner ear if frequency of the wave is 1 kHz $v_{f l u i d} = 1500 m s^{- 1}$

4.4 \times 10^{- 11} m

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4.4 \times 10^{- 10} c m

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4.4 A^{o}

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4.4 p m

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Solution

The correct option is B $4.4 \times 10^{- 11} m$
$R_{i n n e r e a r} = \frac{ω}{v} = \frac{1000 \times 2 π}{1500} = \frac{4 π}{3}$
$y_{0} = \frac{P_{m a x} (i n n e r)}{B_{f l u i d} R_{i n n e r e a r}}$
$= \frac{0.4 \times 45 \times 10^{- 11}}{\frac{4 π}{3}} = 4.4 \times 10^{- 11} m$

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Find the maximum displacement in the fluid of inner ear if frequency of the wave is 1 kHz vfluid=1500ms−1

The correct option is B 4.4×10−11mRinnerear=ωv=1000×2π1500=4π3y0=Pmax(inner)BfluidRinnerear =0.4×45×10−114π3=4.4×10−11m

Find the maximum displacement in the fluid of inner ear if frequency of the wave is 1 kHz $v_{f l u i d} = 1500 m s^{- 1}$

The correct option is B $4.4 \times 10^{- 11} m$
$R_{i n n e r e a r} = \frac{ω}{v} = \frac{1000 \times 2 π}{1500} = \frac{4 π}{3}$
$y_{0} = \frac{P_{m a x} (i n n e r)}{B_{f l u i d} R_{i n n e r e a r}}$
$= \frac{0.4 \times 45 \times 10^{- 11}}{\frac{4 π}{3}} = 4.4 \times 10^{- 11} m$