Find the maximum force that should act on the $7 kg$ body for the system to accelerate together with $1 {m/s}^{2}$ . Take $g = 10 {m/s}^{2}$ .

15 N

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20 N

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30 N

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50 N

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Solution

The correct option is C $30 N$
We know that by formula,

$F_{max} = (m_{1} + m_{2}) (μ_{1} g + a_{s})$
$(m_{1} = 7 kg; m_{2} = 3 kg; μ_{1} = 0.2; μ_{2} = 0.3)$
$a_{s} = 1 {m/s}^{2}$
$= (3 + 7) (0.2 \times 10 + 1)$
$= 10 \times 3 = 30 N$

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A force of 50N produces an acceleration of 10m/s²on a body of mass m₁ and an acceleration of 20m/s² on a body of mass m_2.Find the acceleration produced by the same force if both the bodies were tied together.

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Find the maximum force that should act on the 7 kg body for the system to accelerate together with 1 m/s2. Take g=10 m/s2.

The correct option is C 30 NWe know that by formula, Fmax=(m1+m2)(μ1g+as) (m1=7 kg; m2=3 kg; μ1=0.2; μ2=0.3) as=1 m/s2 =(3+7)(0.2×10+1) =10×3=30 N

Find the maximum force that should act on the $7 kg$ body for the system to accelerate together with $1 {m/s}^{2}$ . Take $g = 10 {m/s}^{2}$ .

The correct option is C $30 N$
We know that by formula,

$F_{max} = (m_{1} + m_{2}) (μ_{1} g + a_{s})$
$(m_{1} = 7 kg; m_{2} = 3 kg; μ_{1} = 0.2; μ_{2} = 0.3)$
$a_{s} = 1 {m/s}^{2}$
$= (3 + 7) (0.2 \times 10 + 1)$
$= 10 \times 3 = 30 N$