Question

Find the maximum number of angle, which are less than ${90}^{\circ }$ in $I{F}_5$.

• A. $0$
• B. $4$
• C. $8$
• D. $12$

Answer 1

The correct option is B $4$

The maximum number of angle, which are less than ${90}^o$ in $I{F}_5$ is $4$.

The central $I$ atom has $5$ bond pairs and one lone pair of electrons. It undergoes $s{p}^3{d}^2$ hybridization. The expected geometry is octahedral and the actual geometry is square pyramidal. The bond angles are less than ${90}^o$ due to repulsion between lone pair and bond pairs of electrons.