Find the maximum speed at which a car can turn sound a curve $30 m$ radius on a level road. Coefficient of friction between tyres and road is $0.11$

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Solution

Frictional force= centrifugal force

$f m g = \frac{m v^{2}}{r}$

By substituting the values in the above equation we get

$v_{max} = \sqrt{μ g r}$

$0.11 = \frac{v^{2}}{9.8 \times 30}$

Hence the maximum velocity is

$5.68 m / s$

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Find the maximum speed at which a car can turn sound a curve 30m radius on a level road. Coefficient of friction between tyres and road is 0.11

Frictional force= centrifugal force fmg=mv2r By substituting the values in the above equation we get vmax=√μgr 0.11=v29.8×30 Hence the maximum velocity is 5.68m/s

Find the maximum speed at which a car can turn sound a curve $30 m$ radius on a level road. Coefficient of friction between tyres and road is $0.11$

Frictional force= centrifugal force

$f m g = \frac{m v^{2}}{r}$

By substituting the values in the above equation we get

$v_{max} = \sqrt{μ g r}$

$0.11 = \frac{v^{2}}{9.8 \times 30}$

Hence the maximum velocity is

$5.68 m / s$