wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Find the maximum value of 4sin2x+3cos2x+sinx2+cosx2 is

A
4+2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
3+2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
9
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
4
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 4+2
Max. value of 4sin2x+3cos2x=sin2x+3 is 4 hold at x=x2s and max. value of sinx2+cosx2 is 2 at x=π2
Since the maximum value occurs at the same point for the two expressions, the maximum value of 4sin2x+3cos2x+sinx2+cosx2 is 4+2

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Algebra of Derivatives
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon