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Question

# Find the maximum value of F such that both the blocks move together. Take g=10 m/s2.

A
200 N
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B
150 N
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C
100 N
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D
50 N
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Solution

## The correct option is B 150 NAs we know that, for maximum value of force F, the friction will be limiting. Also, as per given condition, both the blocks are moving together. We have FBDs of both the blocks as We have N1=10g=100 N N2=N1+20g=100+200=300 N f=flimiting=fmax=μN1=0.5×100=50 N ∵ the blocks moves together, the common acceleration is given by ac=FmA+mB=F10+20=F30 m/s2 Now, from the FBD of block B we have F−f=mBac⇒ F−50=20×F30 ⇒ (F−2F3)=50 ⇒ F=3×50=150 N

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