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Question

Find the maximum value of x that satisfies the following inequation:
3(x7)157x>x+13; xW.
  1. 1

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Solution

The correct option is A 1

Given: 3(x7)157x>x+13

let's separate the given inequation in two inequations as shown below:

3(x7)157x3x+21157x4x6x64x1.5∣ ∣ ∣ ∣ ∣ ∣157x>x+131513>x3+7x4513>x+21x344>22x2>x

1.5x<2

The same solution set can be represented on the number line as shown below:


The whole numbers lying between -1.5 and 2 are: 0 and 1. Hence, the maximum value of x that satisfies the inequation is 1.


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