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Question

# Find the mean age in years from the frequency distribution given below: Class interval of age in yearsFrequency(fi)25−29430−351435−392240−451645−49650−55555−593Total70

A

39.35

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B

29.39

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C

40.15

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D

40.39

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Solution

## The correct option is A 39.35 Class mark for first class interval = Upper class limit + Lower class limit2=25+292=27 Similarly the class mark for each class interval can be found. Class intervalFrequency(fi)Class mark(xi)fixi25−2942710830−35143244835−39223781440−45164267245−4964728250−5555226055−59357171Total∑fi=70∑fixi=2755Mean=∑fixi∑fi=275570=39.4

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