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Question

# Find the mean age in years from the frequency distribution given below: Class interval of age in yearsFrequency(fi)25âˆ’29430âˆ’351435âˆ’392240âˆ’451645âˆ’49650âˆ’55555âˆ’593Total70

A
39.35
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B
38.39
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C
40.15
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D
40.39
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Solution

## The correct option is A 39.35Class mark for first class interval =Upper class limit + Lower class limit2=25+292=27 Similarly the class mark for each class interval can be found. Class intervalFrequency(fi)Class mark(xi)fixi25−2942710830−35143244835−39223781440−45164267245−4964728250−5555226055−59357171Total∑fi=70∑fixi=2755 Mean=∑fixi∑fi=275570=39.4

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