Find the mean age in years from the frequency distribution given below-Wline Class interval of age in years - Frequency fi Whine 25-30 - 4 Wline 30-35 - 1411Wline 35-40 - 2211Wline 40-45 - 16 Wline45-50 - 6 Whine 50-55 - 5 1Whine 55-60 - 3 Whine Total - 70 1Whine lend array A- 39-85B- 39-40C- 40-15D- 40-39

The correct option is A 39.85 Class mark for first class interval = Upper class limit + Lower class limit/2 = 25 + 30/2= 27.5 Similarly the class mark for each ...

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Standard VIII

Mathematics

Direct Method of Finding Mean

Find the mean...

Question

Find the mean age in years from the frequency distribution given below:
$\begin{matrix} C l a s s i n t e r v a l o f a g e i n y e a r s & F r e q u e n c y (f_{i}) 25 - 30 & 4 30 - 35 & 14 35 - 40 & 22 40 - 45 & 16 45 - 50 & 6 50 - 55 & 5 55 - 60 & 3 T o t a l & 70 \end{matrix}$

39.85

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39.40

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40.15

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40.39

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Solution

The correct option is A
39.85

Class mark for first class interval $= \frac{Upper class limit + Lower class limit}{2} = \frac{25 + 30}{2} = 27.5$
Similarly the class mark for each class interval can be found.
$\begin{matrix} C l a s s i n t e r v a l & F r e q u e n c y (f_{i}) & C l a s s m a r k (x_{i}) & f_{i} x_{i} 25 - 30 & 4 & 27.5 & 110 30 - 35 & 14 & 32.5 & 455 35 - 40 & 22 & 37.5 & 825 40 - 45 & 16 & 42.5 & 680 45 - 50 & 6 & 47.5 & 285 50 - 55 & 5 & 52.5 & 262.5 55 - 60 & 3 & 57.5 & 172.5 T o t a l & \sum f_{i} = 70 & \sum f_{i} x_{i} = 2790 \end{matrix} M e a n = \frac{\sum f_{i} x_{i}}{\sum f_{i}} = \frac{2790}{70} = 39.85$

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Find the mean age in years from the frequency distribution given below: Class interval of age in yearsFrequency(fi)25−30430−351435−402240−451645−50650−55555−603Total70

Find the mean age in years from the frequency distribution given below:
$\begin{matrix} C l a s s i n t e r v a l o f a g e i n y e a r s & F r e q u e n c y (f_{i}) 25 - 30 & 4 30 - 35 & 14 35 - 40 & 22 40 - 45 & 16 45 - 50 & 6 50 - 55 & 5 55 - 60 & 3 T o t a l & 70 \end{matrix}$