Find the mean age in years from the frequency distribution given below:
Class interval of age in yearsFrequency(fi)25−30430−351435−402240−451645−50650−55555−603Total70
39.85
Class mark for first class interval =Upper class limit + Lower class limit2=25+302=27.5
Similarly the class mark for each class interval can be found.
Class intervalFrequency(fi)Class mark(xi)fixi25−30427.511030−351432.545535−402237.582540−451642.568045−50647.528550−55552.5262.555−60357.5172.5Total∑fi=70∑fixi=2790Mean=∑fixi∑fi=279070=39.85