Find the mean of the following data, by using the assumed mean method.
Class Interval
$0 - 10$
$10 - 20$
$20 - 30$
$30 - 40$
$40 - 50$
Frequency
$7$
$8$
$12$
$13$
$10$

10

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30

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27.2

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None of these

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Solution

The correct option is C $27.2$
Answer:-

Class interval Frequency ( $f_{i}$ ) $x_{i} = \frac{lower limit + upper limit}{2}$ $f_{i} x_{i}$
$0 - 10$ $7$ $5$ $35$
$10 - 20$ $8$ $15$ $120$
$20 - 30$ $12$ $25$ $300$
$30 - 40$ $13$ $35$ $455$
$40 - 50$ $10$ $45$ $450$
$Σ f_{i} = 50$ $Σ f_{i} x_{i} = 1360$
Mean = $\frac{Σ f_{i} x_{i}}{Σ f_{i}} = \frac{1360}{50} = 27.2$

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Similar questions

Class interval	$10 - 15$	$15 - 20$	$20 - 25$	$25 - 30$
Frequency	$7$	$12$	$8$	$10$

Class Interval	$20 - 30$	$30 - 40$	$40 - 50$	$50 - 60$	$60 - 70$	$70 - 80$
Frequency	$10$	$6$	$8$	$12$	$5$	$9$

Class interval	$0 - 10$	$10 - 20$	$20 - 30$	$30 - 40$	$40 - 50$	$50 - 60$	$60 - 70$	$70 - 80$
Frequency	$5$	$8$	$7$	$12$	$28$	$20$	$10$	$10$

Class interval	$0 - 10$	$10 - 20$	$20 - 30$	$30 - 40$	$40 - 50$	$50 - 60$
Frequency	$5$	$10$	$25$	$16$	$12$	$8$

= 25

$C . I$	$0 - 10$	$10 - 20$	$20 - 30$	$30 - 40$	$40 - 50$
$f$	$7$	$10$	$15$	$8$	$10$

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Class interval	Frequency ( $f_{i}$ )	$x_{i} = \frac{lower limit + upper limit}{2}$	$f_{i} x_{i}$
$0 - 10$	$7$	$5$	$35$
$10 - 20$	$8$	$15$	$120$
$20 - 30$	$12$	$25$	$300$
$30 - 40$	$13$	$35$	$455$
$40 - 50$	$10$	$45$	$450$
	$Σ f_{i} = 50$		$Σ f_{i} x_{i} = 1360$