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Question

Find the Median for the given data by drawing a 'less than ogive' :

Class Interval0−1010−2020−3030−4040−50Frequency51014168


A

35

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B

28

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C

29

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D

31

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Solution

The correct option is C

29


To draw the Less than Ogive , first we prepare the Cumulative frequency table as given below :

ObservationsFrequencyObservationsCumulative(in classes)(in 'less than' form) Frequency0105Less than 105102010Less than 2015203014Less than 3029304016Less than 404540508Less than 5053

Now, we mark the upper class limits along the x-axis on a suitable scale and the corresponding Cumulative Frequencies along the y-axis on a suitable scale.

We plot the points (0,0) , (10,5) , (20,15) , (30,29) , (40,45) and (50,53).

We join the plotted points by a freehand curve to obtain the required ogive as shown in the Graph :

Total number of observations = n = 53

To find the median from this ogive , first we locate the number n2 = 532 = 26.5 on the y - axis

From the point marked 26.5 on the y - axis , we draw a horizontal line parallel to the x - axis intersecting the ogive at point A. From the point A , we draw a vertical line perpendicular to the x - axis meeting it at B. the value of point B on the x - axis is 29.

Hence, the required Median is 29.


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