1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

# Find the Median for the given data by drawing a 'less than ogive' : Class Interval0−1010−2020−3030−4040−50Frequency51014168

Open in App
Solution

## To draw the Less than Ogive , first we prepare the Cumulative frequency table as given below : ObservationsFrequencyObservationsCumulative(in classes)(in 'less than' form) Frequency0−105Less than 10510−2010Less than 201520−3014Less than 302930−4016Less than 404540−508Less than 5053 Now, we mark the upper class limits along the x-axis on a suitable scale and the corresponding Cumulative Frequencies along the y-axis on a suitable scale. We plot the points (0,0) , (10,5) , (20,15) , (30,29) , (40,45) and (50,53). We join the plotted points by a freehand curve to obtain the required ogive as shown in the Graph : Total number of observations = n = 53 To find the median from this ogive , first we locate the number n2 = 532 = 26.5 on the y - axis From the point marked 26.5 on the y - axis , we draw a horizontal line parallel to the x - axis intersecting the ogive at point A. From the point A , we draw a vertical line perpendicular to the x - axis meeting it at B. the value of point B on the x - axis is 29. Hence, the required Median is 29.

Suggest Corrections
2
Join BYJU'S Learning Program
Related Videos
Median
MATHEMATICS
Watch in App
Explore more
Join BYJU'S Learning Program