Question

Find the median of the data: $35,48,92,76,64.52,51,63$ and $71$

• A. $71$
• B. $64$
• C. $52$
• D. $48$

Answer 1

The correct option is B $64$

Arranging the data in ascending order:
$35,48,51,52,63,64,71,76,92$
Mean $=\frac{\text{sum of all numbers}}{\text{count of all numbers}}=\frac{35+48+51+52+63+64+71+76+92}{9}=\frac{552}{9}=61.33$

Since the number of data is odd the median will be the middlemost term.

So, Median $=63$ of the numbers would become:

$35,48,52,63,64,66,71,76,92$

The new Median is $64$.