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Question

Find the middle term in the expansion of (5x7y)7.

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Solution

Since n is an odd number, the expansion contains two middle terms.
(7+12)th and (7+32)th terms are the two middle terms in the expansion of (5x - 7y)7
T4=T3+1=(1)37C3(5x)73(7y)3
=7C3(5x)4(7y)3
T5=T4+1=(1)47C4(5x)74(7y)4
=7C4(5x)3(7y)4

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