Find the minimum horizontal force (F) needed to start the slipping at any part of the system. (Take g=10m/s2)
A
20N
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
30N
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
60N
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
40N
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is C60N First of all we need to check what is the friction available for all the three blocks. For Block (A): N1=30g=300N f3 max=μN1=(0.3)(300)=90N
For Block (B):
N=40g=400N f2 max=μN=0.2×400=80N
Similarly, for block (C):
N=60g=600N f1 max=μN=(0.1)×600=60N
So, the minimum driving force required to start slipping at any point of the system is 60N.