Find the minimum value of force F for which the system remains at rest. Take g=10m/s2.
A
60N
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B
72N
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C
80N
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D
90N
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Solution
The correct option is B72N The FBDs of the system can be shown as:
The 4kg block will try to move towards right, so the frictional force f will act on it towards left.
Thus, from the figure shown, we can write the equation of force as (a)T=8g (b)T=F+f=F+μ(4g) From the above two equations we get ⇒8g=F+0.2×4×10 ⇒F=80−8=72N