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Question

Find the minimum value the function f(x)=π216cot1(x)cot1x

A
π4
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B
π2
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C
0
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D
π2
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Solution

The correct option is B π2
f(x)=π216cot1(x)(πcot1(x))
=cot1(x)+π216cot1(x)π
=⎜ ⎜cot1(x)+π4cot1(x)⎟ ⎟2+π2π,

Since [cot1θ>0]π2
fmin=π2

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