Question

Find the missing values in the table using the given information:

$\text{Column 1 : Column 2}=2:3$
$\text{Row 1 : Row 2}=1:4$

• A. A = 3 ; B = 8 ; C = 12
• B. A = 3 ; B = 8 ; C = 18
• C. A = 8 ; B = 3 ; C = 12
• D. A = 8 ; B = 3 ; C = 18

Answer 1

The correct option is A A = 3 ; B = 8 ; C = 12

$Given:$
$\text{Column 1 : Column 2}=2:3$

$\text{The ratio}2:3\text{can be expressed as the}\text{fraction}\frac{2}{3}$

$\therefore \text{When the value in column 1 is 2, the value}$ $\text{in column 2 will be 3.}$

$⟹A=3$

$Given:$
$\text{Row 1 : Row 2}=1:4$

$\text{The ratio}1:4\text{can be expressed as the}\text{fraction}\frac{1}{4}$

$\text{Multiplying both the numerator and the}\text{denominator by 2, we get:}$

$\frac{1}{4}=\frac{1\times 2}{4\times 2}=\frac{2}{8}$

$\therefore \text{When the value in row 1 is 2, the value}$ $\text{in row 2 will be 8.}$

$⟹B=8$

$\text{Also, multiplying both the numerator and the}\text{denominator by 3, we get:}$

$\frac{1}{4}=\frac{1\times 3}{4\times 3}=\frac{3}{12}$

$\therefore \text{When the value in row 1 is 3, the value}$ $\text{in row 2 will be 12.}$

$\text{As we found out, A = 3}$

$⟹C=12$