Find the mode of the given data: [CBSE 2015]

Class interval 0−20 20−40 40−60 60−80

Frequency 15 6 18 10

Open in App

Solution

Here the maximum class frequency is 18, and the class corresponding to this frequency is 40−60.

So, the modal class is 40−60.

Now,

Modal class = 40−60, lower limit (l) of modal class = 40, class size (h) = 20,

frequency (f₁) of the modal class = 18,

frequency (f₀) of class preceding the modal class = 6,

frequency (f₂) of class succeeding the modal class = 10.

Now, let us substitute these values in the formula:

$Mode = l + (\frac{f_{1} - f_{0}}{2 f_{1} - f_{0} - f_{2}}) \times h = 40 + (\frac{18 - 6}{36 - 6 - 10}) \times 20 = 40 + (\frac{12}{20}) \times 20 = 40 + 12 = 52$

Hence, the mode is 52.

Suggest Corrections

Similar questions

Find the mode of the following data:

Class	0−20	20−40	40−60	60−80
Frequency	15	6	18	10

Class Interval	0-10	10-20	20-40	40-60	60-80	80-100
Frequency	10	8	22	10	20	10

Find the mean, mode and median of the following data: [CBSE 2008]

Class	0−20	20−40	40−60	60−80	80−100	100−120	120−140
Frequency	6	8	10	12	6	5	3

Compute the mode of the following data: [CBSE 2013]

Class	0−20	20−40	40−60	60−80	80−100
Frequency	25	16	28	20	5

Class	0−20	20−40	40−60	60−80	80−100
Frequency	7	p	10	9	13

Join BYJU'S Learning Program