Find the MOI of four identical solid spheres about axis XX′ placed in horizontal plane each of mass M and radius R as shown in figure. Line XX′ touches two spheres (3 and 4) and passes through diameter of other two spheres (1 and 2).
A
910MR2
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B
518MR2
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C
185MR2
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D
95MR2
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Solution
The correct option is C185MR2
MOI of sphere about its COM is [ICOM=25MR2]
So, MOI for sphere 1&2 I1=I2=25MR2
Now, MOI for sphere 3&4 about XX′ by parallel axis theorem, I3=ICOM+MR2 I3=25MR2+MR2 I3=75MR2=I4 ∴ MOI of system about XX′ is I=I1+I2+I3+I4 I=2(25MR2+75MR2) I=185MR2