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Question

# Two identical solid spheres each of mass M and radius R are joined at the two ends of a light rod of length 2R as shown in the figure. The moment of inertia of the system about an axis perpendicular to the length of rod and passing through centre of mass of the two spheres is:

A
22MR25
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B
44MR25
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C
11MR25
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D
33MR25
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Solution

## The correct option is A 44MR25Moment of inertia of the sphere about its center of mass is 25MR2Using the parallel axis theorem we get the moment of inertia about the rotational axis as 25MR2+M(2R)2=225MR2As there are two sphere we get the total moment of inertia as 2×225MR2=445MR2

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