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Question

# Two spheres each of mass M and radius R2 are connected with a massless rod of length 2 R. The moment of inertia of the system about an axis passing through the centre of one of the spheres and perpendicular to the rod is:

A
MR2/10
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B
41 MR2/10
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C
21 MR2/2
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D
5 MR1/2
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Solution

## The correct option is A MR2/10By parallel axis theorem, the moment of inertia of a solid sphere about any parallel axis is I′=I+mx2⇒I′=25M(R2)2+M(2R)2because the moment of inertia of solid sphere is 25MR2∴ Total moment of inertia is 2(25M(R2)2)+M(2R)2 =MR25+4MR2=215MR2

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