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Molality

Find the mola...

Question

Find the molality of 1 M HCl solution having a density of 1.5365 g/mL:

0.67 m

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0.22 m

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0.44 m

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0.33 m

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Solution

The correct option is A 0.67 m
$M a s s o f 1 L s o l u t i o n = v o l u m e \times d e n s i t y$
$= 1.5365 \times 1000 = 1536.5 g$

Mass of solute in 1 L solution $= 1 \times 36.5 = 36.5 g$

Mass of solvent $= 1536.5 - 36.5 = 1500 g$

$M o l a l i t y = \frac{n u m b e r o f m o l e o f H C l}{m a s s o f s o l v e n t i n k g}$

$M o l a l i t y = \frac{1}{1500} \times 1000 = 0.67 m$

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