Question

Find the molarity of a 15% (w/w) $H_{2}S{O}_4$ solution.
(Density of the solution is 1.10 g/mL)

• A. $1.68M$
• B. $2.45M$
• C. $4.58M$
• D. $8.6M$

Answer 1

The correct option is A $1.68M$

15% (w/w) $H_{2}S{O}_4$ $\Rightarrow 15g{H}_{2}S{O}_4$ in 100 g of solution
$\Rightarrow$ 150 g $H_{2}S{O}_4$ in 1000 g solution
$Volumeofthesolution=\frac{\text{Mass}}{\text{density}}=\frac{1000}{1.10}=909mL\text{Molarity}=\frac{\text{Number of moles of Solute}}{\text{volume of solution in L}}$
$\Rightarrow \frac{150\times 1000}{98\times 909}=1.68M$