Question

Find the multiplicative inverse (i.e., reciprocal) of:
(i) $\frac{13}{25}$
(ii) $\frac{-17}{12}$
(iii) $\frac{-7}{24}$
(iv) 18
(v) −16
(vi) $\frac{-3}{-5}$
(vii) −1
(viii) $\frac{0}{2}$
(ix) $\frac{2}{-5}$
(x) $\frac{-1}{8}$

Answer 1

$$\begin{gathered} \text{(i)} \\ \mathrm{Reciprocal}\mathrm{of}\frac{13}{25}\mathrm{is}\frac{25}{13}. \\ \left(\mathrm{ii}\right) \\ \mathrm{Reciprocal}\mathrm{of}\frac{-17}{12}\mathrm{is}\frac{12}{-17},\mathrm{that}\mathrm{is},\frac{-12}{17}. \\ \text{(iii)} \\ \mathrm{Reciprocal}\mathrm{of}\frac{-7}{24}\mathrm{is}\frac{24}{-7},\mathrm{that}\mathrm{is},\frac{-24}{7}. \\ \text{(iv)} \\ \mathrm{Reciprocal}\mathrm{of}18\mathrm{is}\frac{1}{18}. \\ \left(\mathrm{v}\right) \\ \mathrm{Reciprocal}\mathrm{of}-16\mathrm{is}\frac{1}{-16},\mathrm{that}\mathrm{is},\frac{-1}{16}. \\ \text{(vi)} \\ \mathrm{Reciprocal}\mathrm{of}\frac{-3}{-5}\mathrm{is}\frac{-5}{-3},\mathrm{that}\mathrm{is},\frac{5}{3}. \\ \text{(vii)} \\ \mathrm{Reciprocal}\mathrm{of}-1\mathrm{is}-1. \\ \text{(viii)} \\ \mathrm{Reciprocal}\mathrm{of}\frac{0}{2}\mathrm{does}\mathrm{not}\mathrm{exist}\mathrm{as}\frac{2}{0}=\infty . \\ \text{(ix)} \\ \mathrm{Reciprocal}\mathrm{of}\frac{2}{-5}\mathrm{is}\frac{-5}{2}. \\ \text{(x)} \\ \mathrm{Reciprocal}\mathrm{of}\frac{-1}{8}\mathrm{is}-8. \end{gathered}$$