Find the multiplicative inverse of $4 - 3 i$ .

4 + 3 i

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\frac{4 + 3 i}{25}

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\frac{4 - 3 i}{7}

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\frac{4 - 3 i}{25}

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Solution

The correct option is A $\frac{4 + 3 i}{25}$
$4 - 3 i$
Inverse= $(4 - 3 i)^{- 1}$
$= \frac{1}{4 - 3 i}$
On rationalizing = $\frac{4 + 3 i}{16 + 9}$
$= \frac{4 + 3 i}{25}$

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