Find the multiplicative inverse of the following complex numbers.
${(1 + i \sqrt{3})}^{2}$

Open in App

Solution

${(1 + i \sqrt{3})}^{2} = 1 + {(i \sqrt{3})}^{2} + 2 i \sqrt{3}$

$= 1 - 3 + 2 i \sqrt{3}$

$= - 2 + 2 i \sqrt{3}$

Multiplicative inverse is $\frac{1}{- 2 + 2 i \sqrt{3}}$

Suggest Corrections

Similar questions

Find the multiplicative inverse of the following complex numbers :

$(i) 1 - i (i i) (1 + i \sqrt{3})^{2} (i i i) 4 - 3 i (i v) \sqrt{5} + 3 i$

Find multiplicative inverse of the complex number $(2 + \sqrt{3 i})^{2} .$

- i

Find the multiplicative inverse of each of the complex numbers

-i

Join BYJU'S Learning Program