Find the multiplicative of $2 - 3 i$ $a = 2$ , $b = - 3$ .

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Solution

$2 = 2 - 3 i$

Multiplication inverse $= \frac{1}{2} = \frac{1}{2 - 3 i}$

$\Rightarrow \frac{1}{2 - 3 i} \times \frac{(2 + 3 i)}{(2 + 3 i)})$

$\Rightarrow \frac{2 + 3 i}{2^{2} - (3 i)^{2}}$

$\Rightarrow \frac{2 + 3 i}{4 - 9 i^{2}}$

$\Rightarrow \frac{2 + 3 i}{4 + 9}$

$= \frac{2}{13} + \frac{3 i}{13}$

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