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Question

Find the nth term of the sequence 2, 5, 10, 17, 26 ...

A
n2 - 1
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B
n2 + 1
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C
n+2
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D
n+11
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Solution

The correct option is B n2 + 1
T2 = T1 + 3 = 2 + 3 = 22 + 1 = 5
T3 = T2 + 5 = 5 + 5 = 32 + 1 = 10
T4 = T3 + 7 = 10 + 7 = 42 + 1 = 17
T5 = T4 + 9 = 17 + 9 = 52 + 1 = 26

Similarly Tn = n2 + 1

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