(ii) 3x2−4√3x+4=0
Comparing it with ax2+bx+c=0, we get
a=3,b=−4√3 and c=4
Discriminant=b2−4ac
=(−4√3)2−4(3) (4)
=48−48=0Since b2−4ac=0,
Therefore, real roots exist for the given equation and they are equal to each other. And the roots will be −b2aand−b2a.
⇒ −b2a= - (−4√3)2×3 = 4√36 = 2√33 = 2√3
Therefore, the roots are 2√3 and 2√3.