wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Find the nature of the roots of the following quadratic equations. If the real roots exist, find them;
(ii) 3x243x+4=0

Open in App
Solution

(ii) 3x243x+4=0
Comparing it with ax2+bx+c=0, we get
a=3,b=43 and c=4
Discriminant=b24ac
=(43)24(3) (4)
=4848=0Since b24ac=0,
Therefore, real roots exist for the given equation and they are equal to each other. And the roots will be b2aandb2a.
b2a= - (43)2×3 = 436 = 233 = 23
Therefore, the roots are 23 and 23.

flag
Suggest Corrections
thumbs-up
5
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Solving QE by Factorisation
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon