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Question

Find the necessary inductance. if 110 V, 10 W rating bulb is to be used with 220 V A.C source having frequency 50 Hz.

A
L=8.90 H
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B
L=6.75 H
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C
L=7.25 H
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D
L=6.5 H
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Solution

The correct option is B L=6.75 H
Given, V=110v ,P=10W ,V0=220w ,f=50Hz
Current through series inductor,
Current through bulb=PV=10W110V=0.09A
Voltage across inductor,Vind=V20V2=22021102=191V
Reactance of inductor,R=VindI=1910.09=2122.22
Also,R=2πfL or L=R2πf=2122.222π50=6.75H

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