Find the negative of middle term in the expansion of 2x-3-3-2x 6

The middle term will be nbsp; T_4 =T_3+1 = ^6C_3.23^3.(32)^3.x^0 = ^6C_3 = 20 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Greatest Binomial Coefficients

Find the nega...

Question

Find the negative of middle term in the expansion of
${(\frac{2 x}{3} - \frac{3}{2 x})}^{6}$

Open in App

Solution

Suggest Corrections

Similar questions

{(\frac{2 x}{3} - \frac{3}{2 x})}^{6}

{(\frac{2 x}{3} + \frac{3}{2 x})}^{10}

x^{- 2}

{(\frac{2 x}{3} + \frac{3}{2 x})}^{6}

{(\frac{{2 x}^{2}}{3} - \frac{3}{2 x})}^{12}

The middle term in the expansion of ${(\frac{2 x}{3} - \frac{3}{2 x^{2}})}^{2 n}$ is

Join BYJU'S Learning Program