Find the number of elements which satisfies the given inequalities.
−52+2x≤ 4x3≤ 43+2x, where, x ϵ whole number.
4
−52+2x≤ 4x3≤ 43+2x
−5+4x2≤ 4x3≤ 4+6x3 [Multiply with 6 throughout]
3(−5+4x)≤ 8x≤ 2(4+6x)
−15+12x≤ 8x≤ 8+12x
−15+12x≤ 8x;8x≤ 8+12x
−15≤ −4x;−4x≤ 8
154≥ x;x≥−2
So, for satisfying both the inequalities x has {0, 1, 2, 3}. So, 4 elements satisfy the given inequalities.