Question

Find the number of gram-atoms in 88.75 gm of chlorine atom.

$(Cl=35.5)$

• A. 2.5
• B. 88.75
• C. 35.5
• D. 1.25

Answer 1

The correct option is A 2.5

No of moles= $\frac{88.75}{35.5}=2.5$ moles

Therefore, the number of gram-atoms in 88.75g of chlorine is 2.5.

Hence, option $A$ is correct.