Find the number of ions furnished per molecule of the complex [Ni(NH $_{3}$ ) $_{4}$ ]Cl $_{2}$ .

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Solution

The number of ions furnished per molecule of the complex [Ni(NH $_{3}$ ) $_{4}$ ]Cl $_{2}$ is 3.
[Ni(NH $_{3}$ ) $_{4}$ ]Cl $_{2}$ $⇌ [N i (N H_{3})_{4}]^{2 +} + 2 C l^{-}$

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P d {C l}_{4} .6 H_{2} O

H^{+}

The number of ions per mole of the complex [Co(NH₃)₆]Cl₃ in solution will be:

C r C l_{3} .6 H_{2} O

= 3

C l^{-}

= 2

-

= 1

C l^{-}

	Formula	Colour	$C l^{-}$ ions in solution per formula unit
(A)	$C r C l_{3} .6 H_{2} O$	violet	3
(B)	$C r C l_{3} .6 H_{2} O$	light green	2
(C)	$C r C l_{3}^{'} 6 H_{2} O$	dark green	1

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