Find the number of moles of CuSO4.5H2O in a pure sample that contains 0.045 moles of O-atoms.
A
0.5 moles
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B
0.005 moles
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C
50 moles
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D
5 moles
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Solution
The correct option is B 0.005 moles 9 moles of O-atoms are present in 1 mole of CuSO4.5H2O.
So, 0.045 moles of O-atoms will be present in =19×0.045 moles = 0.005 moles of CuSO4.5H2O