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Redox Reactions

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Question

Find the number of moles of $K M n O_{4}$ need to oxidise one mole $C u_{2} S$ in acidic medium. The reaction is $K M n O_{4} + C u_{2} S \to M n^{2 +} + C u^{2 +} + S O_{2}$

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Solution

Reaction - $K M n^{+ 7} O_{4} + C u_{2} S \to M n^{+ 2} + 2 C u^{+ 2} + S O_{2}$
Now from balanced reaction, it is evident that $M n^{+ 7}$ changes to $M n^{+ 2}$ and $2 C n^{+}$ is changing to $C n^{+}$ .
So, valency factor of $M n$ is $5$ and $C n$ is $2$ .
Hence, No. of moles of $K M n O_{4} \times 5 =$ moles of $C u \times 2$
No. of moles of $K M n O_{4} = \frac{1 \times 2}{5} = \frac{2}{5}$

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