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Question

Find the number of natural numbers which lie between 108 and 109 which have products of their digits as 6?

A
55
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B
105
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C
81
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D
92
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E
83
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Solution

The correct option is C 81

OPTION C

108<n<109

n is a 9 digit number

Product of 6 is possible in the following cases

Exactly one digit is 6 and the remaining digits are 1

Number of possible numbers= 9

One digit is 2 and the other is 3, remaining are 1 = 9P2 = 72

Total possible numbers =72+9 = 81


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