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Question

Find the number of O-atoms in 23 moles of NO2.

A
4.014×1023
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B
4.014×1020
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C
8.029×1023
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D
8.029×1020
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Solution

The correct option is C 8.029×1023
1 mole of NO2 contains 2 moles of O-atoms.
So, 23 moles of NO2 will contain 43 moles of O-atoms.
Again, 1 mole of O-atoms = 6.022×1023 O-atoms
Therefore, 43 moles of O-atoms =43×6.022×1023
=8.029×1023 O-atoms

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