CameraIcon

SearchIcon

MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Pascal Triangle

Find the numb...

Question

Find the number of terms in the expansion of ${(1 + x)}^{101}$ with different power of x ?

Open in App

Solution

The no.of terms in expansion $(1 + x)^{n}$ is $n + 1$
The no.of terms in expansion $(1 + x)^{101}$ is $101 + 1 = 102$

Suggest Corrections

thumbs-up

0

Similar questions

Q. The number of distinct terms in the expansion of

{(x + \frac{1}{x} + x^{2} + \frac{1}{x^{2}})}^{15}

is
(Different power of

x

means different terms)

Q. The number of distinct terms in the expansion of

{(x + \frac{1}{x} + x^{2} + \frac{1}{x^{2}})}^{15}

is/are (with respect to different power of

x

)

Q. The number of distinct terms in the expansion of

{(x + \frac{1}{x} + x^{2} + \frac{1}{x^{2}})}^{15}

is
(Different power of

x

means different terms)

Q. The number of terms in the expansion off

(1 + x)^{101} (1 + x^{2} - x)^{100}

in power of x is :

Q. Number of terms in the expansion of

(x^{1 / 3} + x^{2 / 5})^{40}

with integral power of x is equal to

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Introduction

MATHEMATICS

Watch in App

explore_more_icon

Explore more

Pascal Triangle

Standard XII Mathematics

Join BYJU'S Learning Program

CrossIcon