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Question

The number of distinct terms in the expansion of (x+1x+x2+1x2)15 is
(Different power of x means different terms)

A
60
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B
61
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C
30
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D
31
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Solution

The correct option is B 61
(x+1x+x2+1x2)15=(x3+x+x4+1x2)15=(1+x+x3+x4)15x30=a0+a1x+a2x2+...+a60x60x30

Hence, the total number of terms is 61

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