Question

Find the number of ways of arranging the letters of the word
$INTERMEDIATE$

Answer 1

In word INTERMEDIATE, there are $2I,2T,3E$ and $1N,R,M,D,A$ each.

Total no. of letters $=12$

Since letters are repeating, thus,

Total no. of arrangements $=\frac{12!}{2!\times 2!\times 3!}=19958400$