Find the number of ways of arranging the letters of the word
$I N D E P E N D E N C E$

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Solution

In word INDEPENDENCE, there are $3 N, 4 E, 2 D$ and $1 P, I, C$ each.
Total no. of letters $= 12$
Since letters are repeating, thus,
Total no. of arrangements $= \frac{12!}{3! \times 4! \times 2!} = 1663200$

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