Question

The letters of the word "$INDEPENDENCE$" are arranged in all possible ways. Of these the number of words in which the '$D$'s come together is

• A. $11!$
• B. $\frac{11!}{4!}$
• C. $\frac{11!}{4!3!}$
• D. $\frac{11!}{4!3!2!}$

Answer 1

Answer: (C)

$\frac{11!}{4!3!}$

Total number of letters are 12

Take out 2 D's and put them in as one pack so now we have 11 packets

Now N is repeated three times and E is repeated four times

So total number of ways are $\frac{11!}{4!3!}$