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Question

Find the numbers of terms in the expansion of the following :
(i) (1+3x+3x2+x3)5
(ii) (ab+c)6

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Solution

A) =(1+3x+3x2+x3)5
=((1+x)3)5
=(1+x)15
formula for no. terms =Cn+k1k1
=C15+2121
=C161
=16
B) =(ab+c)6
formula for no. terms =Cn+k1k1
=C6+3131
=C82
=28

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