Question

Find the oxidation number of elements in each case :

$Cl$ in $C{l}_2,HOCl,C{l}_{2}O,Cl{O}_2,KCl{O}_3$ and $C{l}_2{O}_7$.

• A. $0,+1,+1,+4,+5,+7$
• B. $0,+1,+1,+2,+5,+5$
• C. $0,+1,0,+3,+5,+6$
• D. None of the above

Answer 1

The correct option is A $0,+1,+1,+4,+5,+7$

Let X be the oxidation number of chlorine in $C{l}_2$.
$2X=0$
$X=0$
Let X be the oxidation number of chlorine in $HOCl$.
$+1-2+X=0$
$X=+1$
Let X be the oxidation number of chlorine in $C{l}_{2}O$.
$2X-2=0$
$X=+1$
Let X be the oxidation number of chlorine in $Cl{O}_2$.
$X+2(-2)=0$
$X=+4$
Let X be the oxidation number of chlorine in $KCl{O}_3$.
$+1+X+3(-2)=0$
$X=+5$
Let X be the oxidation number of chlorine in $C{l}_2{O}_7$
$2X+7(-2)=0$
$X=+7$